Ordered pairs.....?

Question

How would I find the X -intercepts for these equations

y = x^2 -3x -2

and

y = x^2 -2x + 4

I am desperate.... for some reason I cannot figure this out. Do I need to use the quadratic eqaution and how would I set that up ?

Answer 1

she messed. or you messed?
◙ y=0 =x^2-3x-2, r=sqrt(3^2+4*2) = sqrt(17); x1=(3-r)/2, x2=(3+r)/2; (x1 ◙ y=x^2-2x+4=(x-2)^2; both intercepts are equal, i.e. x1=x2=2; that means that x-axis is tangent to parabola y(x)

Answer 2

Set y = 0 & solve for x:

0 = x² - 3x - 2
0 = (x - 1)(x - 2)
x = 1
x = 2
x-intercepts: (1, 0) & (2, 0).

If the second equation is correct, you'll use the quadratic formula.