4secx-cscx=0?

1 ⤊

2007-02-04 16:27:21 · 3 answers · asked by Christie D 1 in Science & Mathematics ➔ Mathematics

3 answers

Solve for x.

4secx - cscx = 0
4secx = cscx
4/cosx = 1/sinx
4sinx = cosx = √(1 - sin²x)
16sin²x = 1 - sin²x
17sin²x = 1
sin²x = 1/17
sinx = 1/√17
x = arcsin(1/√17)

2007-02-04 16:38:26 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋

I would start by writing sec(x) and csc(x) in terms of sin and cos. From there you can multiply through by sin(x) to get an easily-solved equation in terms of tan(x)...

2007-02-05 00:34:47 · answer #2 · answered by Ben 6 · 0⤊ 0⤋

4secx=cscx
4sinx=cosx
tanx=1/4
x=tan^-1(x)

2007-02-05 00:36:50 · answer #3 · answered by sachin gupta 1 · 0⤊ 0⤋