what two numbers whose sum is 32, and whose difference is 16?
what is the larger number and what is the small number?
2007-02-04 16:24:46 · 11 answers · asked by soul2true 1 in Science & Mathematics ➔ Mathematics
24, 8
To solve this, let x and y be the larger and smaller numbers respectively. Then you have two equations:
x+y = 32 and x-y = 16
add the equations together to get 2x = 48, so x = 24
Plug this into either equations to get: y = 8
2007-02-04 16:28:42 · answer #1 · answered by Phineas Bogg 6 · 1⤊ 0⤋
The two numbers whose sum is 32 is 16 plus 16, and the next one is 32 divided by 2 equals 16. The larger number is 16 and the smaller number is 2.
2007-02-05 00:32:35 · answer #2 · answered by ? 3 · 0⤊ 1⤋
x+y=32, x-y=16. These two equations are the same as your first question. The second equation can be renamed x=16+y. This (x) can now be plugged into the first equaiton to solve for y. (16+y)+y=32, 2y+16=32, 2y=16, y=8. If y=8, then x=24.
2007-02-05 00:31:08 · answer #3 · answered by Scott 2 · 0⤊ 0⤋
24, and 8. 24+8=32, 24-8=16. 24 larger, 8 smaller
2007-02-05 00:29:04 · answer #4 · answered by Ted Protostroy 1 · 0⤊ 0⤋
24 and 8
2007-02-05 00:29:04 · answer #5 · answered by Paige 5 · 0⤊ 0⤋
24-8=16
24+8=32
2007-02-05 01:16:00 · answer #6 · answered by mcdonaldcj 6 · 0⤊ 0⤋
x+y=32
x-y=16
so no will be 24 and 8
2007-02-05 00:33:04 · answer #7 · answered by sachin gupta 1 · 0⤊ 0⤋
24, 8
2007-02-05 00:34:14 · answer #8 · answered by Rhul s 2 · 0⤊ 0⤋
hmmm I think its 24 and 8
2007-02-05 00:33:14 · answer #9 · answered by Anonymous · 0⤊ 0⤋
x+y = 32
x-y = 16
2x = 48
x= 24
24+y = 32
y = 8
24 and 8
2007-02-05 00:28:52 · answer #10 · answered by 7 · 0⤊ 0⤋