Can some one please solve these two math problem for me I need help?

Question

A small company produces both standard and deluxe playhouses. The standard playhouses take 12 hours of labor to produce, and the deluxe playhouses take 20 hours. The labor available is limited to 800 hours per week, and the total production capacity is 50 items per week. Existing orders require the company to produce at least 10 standard playhouses and 15 deluxe playhouses per week. Write a system of inequalities representing this situation, where x is the number of standard playhouses and y is the number of deluxe playhouses.

Solve the system.x + 2y = 4x + 2y = –2

Answer 1

Previous answer had second part right, but was wrong and incomplete in the first part. First, the standard houses only take 12 hours to make, thus:

12x +20y <= 800
x + y <= 50

And then you still have to include the inequalities for the existing orders.

10 <= x
15 <= y



The system is solved as 13angus13 explained... both (x+2y) and (4x+2y) are equaled to -2 each.
4x + 2y = -2
x + 2y = -2
substracting both
4x-x+2y-2y=-2+2
3x = 0
then substitute back in anyone you get:
0+2y=-2 => y = -1 & x = 0

There you have 2 answers in one question... ;)

Answer 2

for the first you have 20x + 20y <= 800 and x + y <= 50


write 2 equations from x +2y = 4x + 2y = -2 ..
x + 2y = -2 and 4x + 2y = -2 by elimination method (subtracting the first from the second equation) we'll get 3x = 0 or x = 0..then solve for y using either equations you'll get y = -1 //answer