4x^2 -3x +3 =0
?????????????
I know its already set up in the perfect quadratic equation form but I am lost on how to complete the problem
2007-02-04 15:56:41 · 6 answers · asked by CookFrNW 3 in Science & Mathematics ➔ Mathematics
4x^2 -3x +3 =0
x=(3+/-√(9-4*4*3))/8
x=(3+/-√(-39))/8
x=(3+/-√39)/8
x=.375+.125√39 i, .375-.125√39 i
2007-02-04 16:01:55 · answer #1 · answered by yupchagee 7 · 15⤊ 0⤋
I fiddles around with the numbers and got x=0
I did: 4x^2-3x+3=0, move 3, 4x^2-3x=-3, move 3x, 4x^2=-3+3x, divide by x, 4x=-3+3, simplify, 4x=0, simplify farther, x=0
2007-02-05 00:11:22 · answer #2 · answered by Ted Protostroy 1 · 0⤊ 0⤋
x= -b +/- sqrt(b^2-4ac)/2a
where a=4
b=-3
c=3
You just have to memorize this quadratic formula
2007-02-05 00:05:12 · answer #3 · answered by SWH 6 · 0⤊ 0⤋
3/8 +- sqrt(39)i/8
2007-02-05 00:23:26 · answer #4 · answered by bimands 1 · 0⤊ 0⤋
Please follow the answer above for exact answers and the link that i have given you for further problems similar in nature
2007-02-05 00:07:06 · answer #5 · answered by Smufguy 2 · 0⤊ 1⤋
don't they have scientific calculators for that stuff?
2007-02-05 00:00:15 · answer #6 · answered by Hazel 4 · 0⤊ 1⤋