the weight of a metal sphere varies directly with the cube of it's radius,the weight of a metal sphere of radius 3 is 4.06 kg.calculate the weight of a metal sphere with a radius of 5
2007-02-04 14:30:38 · 9 answers · asked by Boffin 2 in Science & Mathematics ➔ Mathematics
weight of metal = m
radius of metal = r
k = constant
m = k r^3
4.06 = k (3)^3---(1)
m = k (5)^3----(2)
(2)/(1)
m/4.06 = (5/3)^3
m = 4.06 (5/3)^3
m = 18.796 kg
2007-02-04 14:35:32 · answer #1 · answered by seah 7 · 1⤊ 0⤋
Let
w = weight of sphere with 5 inch radius
w = (5/3)³(4.06) = (125/27)(4.06) = 18.796296 kg.
2007-02-04 22:40:57 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
3^3 = 27
5^3 = 125
4.06 kg / 27 * 125 = 18.7962963kg
2007-02-04 22:38:35 · answer #3 · answered by Tim P. 5 · 0⤊ 0⤋
w=kr^3
4.06=k*3^3
k=4.06/3^3
w=4.06/3^3*5^3 = 18.796
2007-02-04 22:42:08 · answer #4 · answered by rwbblb46 4 · 0⤊ 0⤋
k*3^3=4.06
k=0.150
k*5^3=18.8kg
2007-02-04 22:35:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I would think 6.77 kg
2007-02-04 22:33:58 · answer #6 · answered by rblewis7 2 · 0⤊ 1⤋
18.796 kg
2007-02-04 22:33:15 · answer #7 · answered by Vincent G 7 · 0⤊ 0⤋
18.7963
2007-02-04 22:39:59 · answer #8 · answered by chocolahoma 7 · 0⤊ 0⤋
uhhhhhhhh
2007-02-04 22:32:47 · answer #9 · answered by ... 2 · 0⤊ 4⤋