6'' diam. pipe runs 50' high, pipe needs to be drained. How many gallons of water will need to be drained? I have tried the formula pi x r2 x h, but in the book the answer is 73.6 gallons. Tried different ways of getting the answer and its killing me not to get this answer.
2007-02-04 14:26:29 · 5 answers · asked by Aguiñaga 1 in Science & Mathematics ➔ Mathematics
You didn't say how you had attempted to get the solution. First you need to determine the volume of the pipe (cylinder) in cubic inches then convert that volume to gallons - here's how!
Your pipe has a 6" diameter and a height of 50' (which is 600").
The volume of a cylinder, as you stated, is pi (r^2)(h). That's the area of the circular portion of the pipe times the height of the pipe. Don't forget the 'r'(radius) in this case is 3", not 6".. So, pi(3"^2)(600")=3.14(9")(600")= 16956 cu. in. and 1 cu.in. of water equals .00438 gallons. So.............
16956 cu.in x .00438 gallons=74.267 gallons. Your book was close.
2007-02-04 15:14:11 · answer #1 · answered by popcorn 3 · 0⤊ 0⤋
The volume of the pipe is indeed
V = πr²h
We have
r = 6/2 = 3"
h = 12*50 = 600"
V = πr²h = V = π(3²)(600) = π(9)(600) = 5400π in³ ≈ 16964.6 in³
There are 231 cubic inches per US gallon
V = 5400π in³/(231 in³/gallon) ≈ 73.44 gallons
2007-02-04 14:37:37 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
The volume of a pipe is the cross-section (pi*r^2) times the length.
6" diameter means 3" radius, so the cross section is
pi * 3^2 = 9pi square inches.
The pipe is 50' high, so that's 50*12 = 600 inches.
600 inches * 9pi square inches = 5400pi cubic inches
1 gallon is 231 cubic inches, so
5400pi/231 = 23.38*pi gallons,
(about 73.44 gallons).
2007-02-04 14:35:50 · answer #3 · answered by Tim P. 5 · 0⤊ 0⤋
pi r^2 h will give you the volume now factor in the desity of water.
2007-02-04 14:33:12 · answer #4 · answered by haitech82 2 · 0⤊ 1⤋
problematic subject. lookup with yahoo. that could actually help!
2015-03-17 16:38:05 · answer #5 · answered by jason 2 · 0⤊ 0⤋