What is the total acceleration in m/s^2 of a bug on the rim of a 8.0 in. diameter disk if the disk moves from rest to an angular speed of 76 revolutions per minute in 5.0 s? And what is the degree(relative to the tangential acceleration)?
I found all of this information out about the problem:
tangential acceleration=.162
tangential velocity=.81192
tangential acceleration=.162
centripetal acceleration=.259
Thanks for helping!!!
2007-02-04 14:00:14 · 1 answers · asked by Tennis2127 2 in Science & Mathematics ➔ Physics
You are VERY close!
The total acceleration = (Acentripetal^2 + Atangential^2)^(1/2)
They are perpendicular components of the accelerations. To get the angle, draw a diagram and you will see that the acceleration points in a direction that makes an agle of arctan(Acetripetal/Atangential) with respect to the tangential acceleration.
2007-02-04 14:09:49 · answer #1 · answered by Dennis H 4 · 0⤊ 0⤋