how do i find the equation of the line going through (5,3) and (2,9)?

Answer 1

FIRST:
find the slope
(3-9)/(5-20)= -6/3= -2

SECOND:
write out the equation with the slope, plug in one of the points, and solve for b.

y=2x+b
9=-2(2)+b
9=-4+b
13=b

equation:

y=-2x+13

LAST:

check your answer by plugging in x from the other point and see if you get the same y.

y=-2(5)+13
y=-10+13
y=3

(5,3) yes, it works!!!

HERE'S ANOTHER WAY:

you can set up a systems of equations.

3=5m+b
9=2m+b

if you subtract them, u get

-6=3m
m=-2

NEXT:

add the newly found slope to one of the equations and solve for b.

3=5(-2)+b
3=-10+b
b= 13

again, the equation is
y=-2x+13


HOPE THIS HELPS!!! :)

Answer 2

The formula for the slope:
m=(y2-y1)/(x2-x1)
m=(9-3)/(2-5)
m=6/-3=-2

Point-slope formula:
y-y1=m(x-x1)
y-3=-2(x-5)
y-3=-x+10
y=-2x+13

Answer 3

if u r finding the equation of a straight line, then the equation is given by

y = mx + c

where (x, y) are the coordinates, m being the gradient of line and c is the constant at the point whereby the line intersect at the y-axis

Answer 4

first you can use the basic slope intercept form formula which is y=mx+b. then you can find the slope of the line using these two points to get M. Set your x variable to 0 and solve for Y and vice versa.

Answer 5

m = slope = (y2 - y1) / (x2-x1)
Let (x1, y1) = (5,3)
Let (x2, y2) = (2,9)

m = (9-3) / (2-5) = 6/-3 = -2

y-y1 = m(x-x1) ["Point-Slope Equation"]
y-3 = -2(x-5)

Answer 6

find the slope then use the point slope formula

Answer 7

distance= _____________
..............V(x1-x2)+(y1-y2)

MIGHT HELP?