math problem.?

Question

The total cost of the dress and shoes is $196. The dress cost three times as much as the shoes. How much did the dress cost??

Answer 1

d+s=$196

d=3s

4s=196(divide by 4)

s=49

then u subsitute the 49 in where the s would be in the equasion d=3s so then d=147

so the shoes were $49 and the dress is $147 dollars

i hope that helps i learned that in algebra this year

Answer 2

Take the cost of shoes as x
Then cost of dress = 3x
total cost of the dress and shoes = $196
ie, 3x+x = 196
4x = 196
x = 196/4
= 49
So, cost of shoes = $49
so, cost of dress =3x = 3*49 = $147

Answer 3

The dress costs $147. x+3x= $196
4x=196
x= $49 [shoes]
3*49= 147 [dress]

Answer 4

Set up the problem with variables.

Set the cost of the shoes as variable x.

196 = 3x + x

196 = 4x

x = 49

The shoes are $49 and the dress is $147.

Answer 5

d = dress
s = shoes
d + s = 196
d = 3s

3s + s = 196
4s = 196
s = 196 : 4
s = $ 49

d = 3s
d = 3(49)
d = $ 147
Answer: The dress costed $ 147.
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Answer 6

okay so the total is 196
let x = the amount of the shoes
x + 3x = 196
add the x's together so you get:
4x = 196
divide by 4 on both sides
x = 49
so the shoes cost $49
multiply that by 3
the dress cost $147

Answer 7

let x = cost of shoes
3x = cost of dress
x + 3x = 196
... solve for x, then find 3x for the cost of the dress.

Answer 8

$196 x (3/4)

Answer 9

3x + x = 196

4x = 196

x = 196/4

x = 49

Shoes = 49

Dress = 147

Answer 10

that dress costs $147