Question: a defibrilator is used during a hearth attack to restore the heart to its normal beating pattern. A defibrilator passes 18 A of current through the torso of a person in 2.0 milliseconds. (a) How much charge moves during this time? (b) How many electrons pass through the wires connected to the patient?
My Approach:
(a) I = change(q)/ change(time)
18 A = change(q)/ 2.0e-3 s ----- I converted 2.0 ms to seconds
change(q) = .036 C --- answer
(b) .036 C x (1 electron/1.6e-19 C) = 2.3 x 10^8 electrons --- answer
'preciate the help!
2007-02-04 12:34:40 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
a) All right
b) You have the wrong number, should be 2.25x10^17 electrons
2007-02-04 12:42:44 · answer #1 · answered by Javier 2 · 0⤊ 0⤋
You're correct on the charge, and on your approach to the number of electrons, but your calculations seem to be a bit out. You should wind up with 2.3 x 10^17 electrons. This must be a calculation/typo kind of error since you're out by exactly 9 orders of magnitude - perhaps you accidentally used 1.6e-10 instead of 1.6e-19?
2007-02-04 20:40:18 · answer #2 · answered by Scarlet Manuka 7 · 0⤊ 0⤋