There are 6 players. How many possible teams of 3 can be formed?

Answer 1

If in each team there is only 1 position, then the answer is 20

if in the team there are 3 different positions, say each team has to have 1 center, 1 forward, and 1 guard, then there are 120 possible teams

Answer 2

Let there be players A, B, C, D, E, F

If players A, B, C can make only one team, ie,
ACB, CAB are not valid teams once ABC has been counted, there are 6C3 teams.
nCm is calculated as n!/(m!*(n-m)!)

In this case, n=6, m=3
So number of teamsis 6!/(3!*3!)
= 6*5*4*3*2*1/((3*2*1)*(3*2*1))
= 6*5*4/(3*2) = 20

If you're permitted to have teams ABC, ACB, CAB, etc
then the count is 6P3
which is 6!/3! = 6*5*4*3*2*1/(3*2*1)
= 6*5*4 = 120