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what is the solubility of AgCl in water if Ksp is 1.6x10^-10?

how do u solve for this?

2007-02-04 08:42:44 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Firstly, be aware that the solubility constant is dependent on temperature and pressure. It shouldn't surprise you that the amount of a substance that can be dissolved could change dramatically based on how hot it is. SOme have little change, but some substances change a great deal.

The formula you have shows the amount of AgCl that dissolves and ionizes in water. It is quite a small amount as you can see.

The formula is calulated as follows:

Ksp = (Ag+) (Cl-) / (AgCl) = 1.6x10E-10

this means that for each gram of AgCl, 0.4x10E-5 grams each of the Ag+ and Cl- ions have dissolved.

2007-02-04 08:52:20 · answer #1 · answered by reb1240 7 · 0 0

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