how do you solve the gradiant of a line?

Answer 1

You use the formula and take the gradient... don't you have a book?

Answer 2

If you have a straight line, i.e. of the form y=ax+b, the gradient is 'a'.

However, most problems aren't that user-friendly. If you have anything more complex, you can use differentiation to resolve this matter - assuming you know the equation of the line you are trying to find the gradient of. For each term involving a function of 'x', substitute a new term by multiplying the coefficient of x by the power to which x is raised & reducing the power of x by 1. Take the value of x appropriate to the relevant point on the line & use your 'new' equation - the result will give you the gradient of the line.

If you apply the same principles to the 'new' equation, using the same value of 'x' will give you the rate at which the gradient is changing at that point. I've used this principle to solve questions in mental calculations tests (e.g. "What is the 7th root of 50,000 to 2 decimal places?") without the need for a calculator.

On the other hand, you could even try placing a ruler on the paper so that it just touches the line, see how much of a change there is in the values of 'y' & 'x' between the two ends & divide the one by the other.

Answer 3

gradiant = difference in y-axis / difference in x-axis

(both of the same two points )

Answer 4

Differentiate?

Answer 5

If there are two co-ordinates A & B of the form, (xa, ya) and ( xb,yb).
Then the gradient is calculated as follows;-
ya -yb
_____
xa - xb

Answer 6

y=x-1 or y= x+1, it goes up or dahn, dy/dx, get a maths book and learn it.

Answer 7

divide the vertical distance by the horizontal distance

Answer 8

u can use diffrenciation, i.e. "dy/dx"
y= 3x2
dy/dx= 6x

Answer 9

isn't that slope? i think it's rise over run (rise divided by run) i think

Answer 10

find dy/dx