Genetics Problem?

Question

Hemophilia is a sex-linked disorder carried on the X chromosome. A woman who is a carrier of hemophilia has the genotype X^H X^h also referred to as heterozygous for the trait. A man who has hemophilia is represented as X^h Y. A woman who is heterozygous for hemophilia marries a normal man. What will be the possible phenotypes of their children? How likely is it that their son will inherit the disease?

I got from a Punnett Square that they will all have hemophilia but I am not sure...I think I messed up somehow.

Answer 1

For the Punnett Squart the mother's genotype will be X^H and X^h. The normal male she marries will have a X^H Y genotype. So their progeny outcome will be a X^H X^H non-carrier daughter, a X^H X^h carrier non-symptomatic daughter, a X^H Y non-carrier non-symptomatic son, and a X^h Y carrier symptomatic son. So there's a 50% chance that a son will inherit the disease.

Answer 2

Their son will have a 50/50 chance depending on which X he receives from his mother. The outcome for the children will be. 2:2
2 will be X^h (X^H or Y) and 2 will be X^H (X^H or Y).
2 will have hemophilia, and 2 will not.
There will be 1 boy and 1 girl to have it, and 1 boy and 1 girl who do not.