(2x-3)^2
2007-02-04 05:58:35 · 7 answers · asked by d m 1 in Science & Mathematics ➔ Mathematics
You can't simplify, but you can expand by multiplying.
(2x-3)(2x-3) use FOIL (multiply First, Outside, Inside, Last):
4x^2 - 6x - 6x + 9 and then combine like terms:
4x^2 - 12x + 9
2007-02-04 06:02:40 · answer #1 · answered by NvestR3322 2 · 0⤊ 0⤋
use the "FOIL" Method.
First
Outside
Inside
Last
so (2x-3)(2x-3) the first two number times each other
First 2x*2x = 4x^2
Outside 3x * -3 = -6x
Inside -3 * 2x = -6x
Last -3 * -3 = 9
Add em all up and 4x^2 - 12x + 9
2007-02-04 14:03:49 · answer #2 · answered by gwalman 2 · 0⤊ 0⤋
I would assume something to the effect of 2x²-3², or better yet, 2x²-9
Then again, I'm not very good at algebra, so you might want to wait for someone else to confirm that.
2007-02-04 14:01:14 · answer #3 · answered by amazingant111 3 · 0⤊ 0⤋
this would be the same as taking (2x-3)(2x-3) if you multiply out the brackets you get...
oh ok
4x^2-12x+9
whether that's simpler is another matter...
2007-02-04 14:03:27 · answer #4 · answered by ? 4 · 0⤊ 0⤋
(2x-3)(2x-3)-> 4x^2-12x+9
2007-02-04 14:01:23 · answer #5 · answered by John 1 · 0⤊ 0⤋
(2x-3)(2x-3), then use FOIL and solve for zero.
2007-02-04 14:02:06 · answer #6 · answered by GreenIYD 5 · 0⤊ 0⤋
(2x-3)^2
(2x-3)(2x-3)
(4x^2-6x-6x+9)
(4x^2-12x+9)
2007-02-04 14:01:33 · answer #7 · answered by bluefairy421 4 · 0⤊ 0⤋