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Ok I need to figure out how to get to the square root of -11 however not simply as √11i. For example.
√-18 = √9 X √2 X √-1 or 3√2i so the final answer to √-18 in imaginary numbers as a whole would be 3√2i

I understand the process but I cannot remember how to get to the answer for
√-11

2007-02-04 05:52:01 · 4 answers · asked by Ian M 2 in Science & Mathematics Mathematics

4 answers

the first thing to remember is that: i = √-1
since you can't have a negitive under the square root sign, it makes it an imaginary number which you can then take out:
√-11 =
√11 * (√-1 or i)
therefore the answer would be i√11

(11 cannot be broken down any further because it does not factor; that's why it might have looked different than your prior example)

hope i helped.

2007-02-04 06:12:50 · answer #1 · answered by Anonymous · 0 0

In this case it is √11i because there is nothing you can factor out of 11 that is a perfect square. In the the example you provided of √-18, you could factor the perfect square 9 out of -18 in order to simplify, but with √-11 there is no perfect square to factor out. So it is just √11i.

2007-02-04 13:56:35 · answer #2 · answered by NvestR3322 2 · 0 0

√-11 =
√11 * √-1 =
√11 * i or
i√11

2007-02-04 14:01:30 · answer #3 · answered by Steve A 7 · 0 0

well in this case is would be i*sqrt(11) because 11 is prime and has no factors

2007-02-04 13:57:15 · answer #4 · answered by gwalman 2 · 0 0

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