or the other quarterback?
2007-02-04 04:47:16 · 14 answers · asked by americanmalearlington 4 in Politics & Government ➔ Politics
They will be critical to the coach and his upbringing. If the lead is extended they will be critical of the quarter back and his sense of superiority. If the lead is further extended they will be critical to the other teams fans indicating they are also unfair. When they lose then they will blame Bush and the neo-cons and none of their reasons will make sense. Even though the team is owned by Democrates.
2007-02-04 04:57:50 · answer #1 · answered by Steve 1 · 1⤊ 0⤋
No they will probably want to leave, saying they never would have started playing in the first place. Or they will keep "playing", actually arguing back and forth with no real plays or ideas on how to win until they have lost. Then they will blame Bush.
2007-02-04 04:51:30 · answer #2 · answered by Chester's Liver 2 · 1⤊ 0⤋
I was not aware that there was a Democratic, or a Republican team. Both paties seem equally bent on criticism, but I doubt that either will take it into the Super Bowl.
2007-02-04 04:51:33 · answer #3 · answered by fangtaiyang 7 · 0⤊ 2⤋
No.
If the Con team is losing at half time, will they start lobbing bombs during Prince's performance in the name of Christianity?
2007-02-04 04:53:06 · answer #4 · answered by Jake 4 · 0⤊ 1⤋
For the Dems, it's always somebody else's fault. They will blame Bush.
2007-02-04 04:49:53 · answer #5 · answered by Anonymous · 2⤊ 1⤋
They will accuse the scoreboard of being made by Diebold and try to sue.
2007-02-04 04:56:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
dems will criticize.
2007-02-04 04:52:17 · answer #7 · answered by i,m here if you need to talk. 6 · 1⤊ 0⤋
Yes, they will want to withdraw to parking lot
2007-02-04 04:50:29 · answer #8 · answered by Anonymous · 1⤊ 1⤋
Of course they will! When is anything ever THEIR fault?
2007-02-04 07:21:46 · answer #9 · answered by texasjewboy12 6 · 0⤊ 0⤋
they will ask for a recount
2007-02-04 04:51:09 · answer #10 · answered by Anonymous · 1⤊ 0⤋