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∫(x-2)/(x^2-4x+9) dx
= ∫(x-2)/[(x-2)^2+5)] dx
= (1/2) ∫1/[(x-2)^2+5)] d[(x-2)^2+5]
= (1/2) ln|(x-2)^2+5|+c

2007-02-04 04:08:11 · answer #1 · answered by sahsjing 7 · 0 0

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