Series circuit 12 V Battery connected to two equal bulbs each with a resistance of 60 ohms.
2007-02-04 03:45:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Energy changes are:-
Battery...chemical to electrical
Bulbs....electrical to light and heat.
You can find the current by using Ohm's law but you must say whether the bulbs are connected in series or in parallel.
2007-02-04 09:45:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Energy change is from zero to a dissipation of 1.2 Watts.
Total resistance is 120 ohms.
Power = volts^2 divided by resistance
= 12 x 12/120 = 1.2
To be pedantic, the resistance of bulbs changes from when they are cold to an increase when they are hot. We have to assume these are hot resistances.
2007-02-04 03:56:10 · answer #2 · answered by efes_haze 5 · 0⤊ 0⤋
not sure what you are asking precisely.
If you are talking changes in types of energy then the battery has a change of chemical energy to electrical energy.
The light bulbs change the electrical energy to light energy and heat, and a small amount of energy will be converted to heat in the wires...
Sorry if this is not exactly what you are after
hth
John
2007-02-04 03:55:44 · answer #3 · answered by lav750 2 · 0⤊ 0⤋
E
= I^2R
= v^2/R
= 12^2/120
= 1.2 W
2007-02-04 03:56:36 · answer #4 · answered by sahsjing 7 · 0⤊ 0⤋
dunno
2007-02-04 03:48:40 · answer #5 · answered by Lor24 5 · 0⤊ 0⤋