The outside dimensions of a picture frame are 39 inches by 29 inches by 29 inches. If its inside dimensions are 32 inches by 20 inches, find the area of the frame itself.
2007-02-04 03:36:59 · 4 answers · asked by Help please 1 in Science & Mathematics ➔ Mathematics
A of outer frame is 39*29=1131sqin
A of inside is 32*20 = 640sq in
now subtract the 2 areas and you are left with the frame alone...draw yourself a picture to help visualize it better...
A=491 sq in
2007-02-04 03:41:56 · answer #1 · answered by k t 4 · 0⤊ 0⤋
the area of the picture frame itself is equal to the area of the outside dimensions less the area of the inside dimensions because area is conserved:
area of frame = (39 * 29) - (32 * 20)
= 1131 - 640
= 491
2007-02-04 03:48:54 · answer #2 · answered by michaell 6 · 0⤊ 0⤋
(39 *29) - (32*20) = area of frame
1131 - 640 = 491 sq. inches
2007-02-04 03:41:32 · answer #3 · answered by keylimeprecision 2 · 0⤊ 0⤋
The area of the rectangle is the sum of the hypotenuse squared.
2007-02-04 03:40:19 · answer #4 · answered by Kwan Kong 5 · 0⤊ 1⤋