factorize this question...i need help!!!!?

Question

8x^3-6x-9y+27y^3
(explain how u have solved it,if u can)THAAAAAAAAAAANNNX!!!

Answer 1

Switch the order so it is 8x^3 + 27y^3 -6x - 9y

The first two are the sum of two cubes: they would factor as

(2x + 3y)(4x^2 - 6xy + 9y^2)

The second two have a common factor of -3; they would factor as

-3(2x + 3y)

Now these two pairs have a common factor of (2x+3y), so they factor as

(2x+3y)(4x^2 - 6xy + 9y^2 - 3)

Hope that explains it

Answer 2

friends, math sums require saving time, methods, energies so that solutions retain the edge students on the right path.

8x^3-6x-9y+27y^3 - (M)

(a+b)^3 = a^3 + b^3 + 3ab (a+b)

thus a^3 + b^3 = (a+b)^3 - 3ab (a+b) ........(1)

let there be a = 2x, b = 3y put in (1), we get

(8x^3 + 27 y^3) = (2x + 3y)^3 - 18 xy (2x + 3y) .......(2) put in (M)

question becomes = [2x + 3y)^3 - 18 xy (2x + 3y)] -6x -9y

= [2x + 3y)^3 - 18 by (2x + 3y)] -3(2x+3y)

= (2x+3y)*[(2x + 3y)^2 - 18 xy -3]

This is the most simplified solution, not the above one's

Answer 3

you can split it up
instead of saying 8x^3-6x-9y+27y^3
you can say
(8x^3-6x)+(-9y+27y^3)
you can take 2x out of (8x^3-6x) = 2x(4x^2-3)
you can take 9y outta (-9y+27y^3) = 9y(3y^2-1)

therefore...... 2x (4x^2-3) + 9y (3y^2-1)

Answer 4

(2x)^3+(3y)^3-3(2x+3y)
[(2x+3y)(4x^2-6xy+9y^2)]
-3(2x+3y)
(2x+3y)[4x^2-6xy+9y^2-3]