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6 answers

1.ab-ex=e
ab=e+ex
b=a/(e+ex)

2. ab-ex=e
e+ex=ab
e(1+x)=ab
e=ab/(1+x)

2007-02-03 21:37:32 · answer #1 · answered by garlic_chili_91 2 · 0 0

ab - ex = e
ab = e + ex
divide both sides by a : b =e + ex / a

2007-02-04 06:01:23 · answer #2 · answered by Anonymous · 0 0

Question 1
ab = e + ex = e(1 + x)
b = e(1 + x) / a

Question 2
ab = e + ex
ab = e(1 + x)
e = ab / (1 + x)

2007-02-04 05:44:37 · answer #3 · answered by Como 7 · 0 0

1.send -ex to the left hand side ab=e + ex....then send b to the left hand side
therefore------------ a=(e+ex)/b

2. firstly take e to the right hand side and ab to the left hand side
-ex-e= -ab......then multiply this equation by -1 to give ex+e=ab..
factorise the right hand side e(x+1)=ab and send (x+1) to the left hand side i.e. e=ab/(x+1)

2007-02-04 05:59:21 · answer #4 · answered by Akshav 3 · 0 0

ab - ex = e
ab = e + ex
b = (e + ex)/a



ab - ex = e
ab = e + ex
ab = e(1 + x)
ab/(1+x) = e

2007-02-04 05:40:07 · answer #5 · answered by Mathematica 7 · 0 0

who cares?

2007-02-04 05:32:51 · answer #6 · answered by Soundguy 2 · 0 0

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