1.ab-ex=e
ab=e+ex
b=a/(e+ex)
2. ab-ex=e
e+ex=ab
e(1+x)=ab
e=ab/(1+x)
2007-02-03 21:37:32
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answer #1
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answered by garlic_chili_91 2
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ab - ex = e
ab = e + ex
divide both sides by a : b =e + ex / a
2007-02-04 06:01:23
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answer #2
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answered by Anonymous
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Question 1
ab = e + ex = e(1 + x)
b = e(1 + x) / a
Question 2
ab = e + ex
ab = e(1 + x)
e = ab / (1 + x)
2007-02-04 05:44:37
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answer #3
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answered by Como 7
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1.send -ex to the left hand side ab=e + ex....then send b to the left hand side
therefore------------ a=(e+ex)/b
2. firstly take e to the right hand side and ab to the left hand side
-ex-e= -ab......then multiply this equation by -1 to give ex+e=ab..
factorise the right hand side e(x+1)=ab and send (x+1) to the left hand side i.e. e=ab/(x+1)
2007-02-04 05:59:21
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answer #4
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answered by Akshav 3
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ab - ex = e
ab = e + ex
b = (e + ex)/a
ab - ex = e
ab = e + ex
ab = e(1 + x)
ab/(1+x) = e
2007-02-04 05:40:07
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answer #5
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answered by Mathematica 7
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who cares?
2007-02-04 05:32:51
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answer #6
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answered by Soundguy 2
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