2007-02-03 20:49:42 · 11 answers · asked by ajoon 1 in Computers & Internet ➔ Programming & Design
Yeah it's free, but only if you have a genuin winxp.
But the validity check can be bypassed. Mail me if you wanna know the trick.
2007-02-04 15:03:56 · answer #1 · answered by babu 2 · 0⤊ 0⤋
Yes absolutely, all you need is an internet connection, navigate your self to microsoft webiste search for IE updates or IE itself and u get the latest version for absolutely free
2007-02-04 06:22:57 · answer #2 · answered by Kushan 1 · 0⤊ 0⤋
yes IE is absolutely free to download from Microsoft website.
I also recommend FireFox browser, it is far more better than IE and more than average people are using the same now a days
2007-02-04 04:59:42 · answer #3 · answered by LemonPro 5 · 0⤊ 0⤋
omg your on the internet and u never typed in internet explorer into the yahoo search bar...you must be drunk here is the first website that pops up as #1 http://www.microsoft.com/windows/downloads/ie/getitnow.mspx
2007-02-04 04:56:47 · answer #4 · answered by jaybe2k37 1 · 0⤊ 0⤋
Yup. Go get it directly here:
http://www.microsoft.com/windows/downloads/ie/getitnow.mspx
http://www.download.com/Internet-Explorer-for-Yahoo/3000-2356_4-10596062.html?tag=lst-0-10
2007-02-04 05:28:12 · answer #5 · answered by ß!ߤ¥ 3 · 0⤊ 0⤋
Use this provide link to get you started:
http://www.microsoft.com/windows/products/winfamily/ie/default.mspx
2007-02-04 04:54:05 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Yes you can and it's totally free. Just go to microsoft.com and download it. matter of fact I just got mine not too long ago and it's really nice I like the tabs the're really helpfull
2007-02-04 04:59:59 · answer #7 · answered by Fabo 4 · 0⤊ 0⤋
if you've got a verified copy of xp with IE there should be no probs
2007-02-04 04:56:29 · answer #8 · answered by iammoza 3 · 0⤊ 0⤋
yes.. Go to www.microsoft.com
2007-02-04 05:07:08 · answer #9 · answered by gnrjohn87 2 · 0⤊ 0⤋
yes got to microsoft and download it.
2007-02-04 04:53:01 · answer #10 · answered by w2pc.com 3 · 0⤊ 0⤋