How do you factorise and then solve x^2=16, x^2+5x+6=0, and 3x^2-10x-8=0?

Answer 1

x^2=16
x^2 - 16 = 0
(x-4) (x+4) = 0
either x-4 = 0, x = 4
or x+4 = 0, x = -4

x^2 + 5x + 6 = 0
(x+2) (x + 3) = 0
Either x = -2 or x = -3


3x^2 -10x - 8= 0
(3x + 2) ( x-4) = 0
Either x = -2/3 or 4

Answer 2

Question 1.
X² = 16
X = 4 , - 4

Question 2.
X² + 5X + 6 = 0
(X + 3)(X + 2) = 0
X = -3, -2

Question 3.
(3X² - 10X - 8) = 0
(3X + 2)(X - 4) = 0
X = - 2/3, 4

Answer 3

x^2=16 x=+-4
x^2+5x+6=0 (x+3)(x+2)=0 x=-3 and x=-2
3x^2-10x-8=0 (3x+2)(x-4)=0 x=-2/3 and x=4

Answer 4

1. X^2=16
X= 16^1/2
X= 4

2. X^2+5x+6=0
(x+3)(x+2)
X1= -3 X2= -2

3. 3x^2-10X-8
(3x-2)(x+4)
X1=3/2 X2=-4

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Answer 5

a million. take the sqrt of both area and also you get x=sqrt of 16=4,-4 2.(x+2)(x+3)=0 take both and the three to the area with the 0 and subtract 2 from the first and three from the second one and also you get -2,-3 because the reply 3.(3x+2)(x-4)=0 make 2 equations from this problem and also you get 3x+2=0 and x-4=0 and subtract 2 on both area on the first one and four on both area to the second one one and also you've were given 3x=-2 and x=4 contained in the first equation you'll divide both area with assistance from 3 and the merely precise answer is x=-2/3, 4

Answer 6

x^2 = 16
x = ± 4

x^2 + 5x + 6 = 0
(x + 2)(x + 3) = 0
x = -3, -2

3x^2 - 10x - 8 = 0
(3x + 2)(x - 4) = 0
x = -2/3, 4

Answer 7

x^2=16
x^2=4^2
equate the bases
i.e. x=4

x^2+5x+6=0
(x+2)(x+3)
either x= -2 or x= -3

3x^2-10x-8=0
3x6^2-12x+2x-8=0
3x(x-4)+2(x-4)=0
(x-4)(3x+2)=0
either x=4 or x= -2/3

Answer 8

x^2= 16
x^-16=0
(x+4)(x-4)=0
x= 4 or -4

x^2+5x+6=0
(x+2)(x+3)=0
x= -2 or -3

3x^2-10x-8=0
(3x+2)(x-4)=0
x= -2/3 or 4

Answer 9

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