what is graham's law of diffusion?

Question

show the formula

Answer 1

this law states that the rate of diffusion of gases is inversely proportional to the square root of it vapour density.

Answer 2

graham's law of diffusion says"the rate of diffusion of the gases is inversely proportional to the square root of its desity"
mathematically R1/R2=D2/D1to the power1/2.
where R1=the rate of diffusion of the firs gas
R2rate of diffusion of the 2nd gas
D1=density of the first gas
D2=density of the 2nd gas.
well its a very imp. law which is used in physics and chemistry both

Answer 3

Graham's Law of Diffusion (equally holds good for Effusion) states that : "The rate of diffusion(r) of a gas is inversely proportional to the square root of its density(d)". That is, r=k/d^1/2.

From this law, one can also say that, r1/r2 = (d2/d1)^1/2
=(Vapour density of gas 2 / Vapour density of gas 1)^1/2
=(Molecular mass of gas 2 / Molecular mass of gas 1)^1/2
[since, molecular mass = 2*Vapour density]

This law also indicates that,
(1) a gas with lower molecular mass will diffuse faster.
(2) the time taken by a certain volume of a gas to diffuse out of a porous membrane is directly proportional to the square root of its molar mass [since, rate = volume / time; i.e., r1/r2 = (v/t1)/(v/t2).

Answer 4

only posting cuz i wanna see the answer.......*i'll never find this post again wtihout posting on it*

i'm a chem e....done fick's law out the @$$......never herad of graham's law.