A belt which is 15 feet long is tightely tied to a cylinder. The diameter of each circle (which is at the both ends of the cylinder) is 1 feet. What is the distance between the centers of 2 circles??? Can anyone help me out with this??
2007-02-03 19:03:21 · 6 answers · asked by rajagopal r 1 in Science & Mathematics ➔ Mathematics
hey ur question is correct
now u know the total length of belt
u just subtract the length of the two circles from total lenth
u get the digonal b/w the circles
apply pythagorous theorm
i am adding the length of circles
2pie * 1/2 + 2pie * 1/2 = 2 pie
now
15-2pie length of digonal
(15-2pie)^2 + (1)^2(diameter of circle)
solve this the answer is the distance b/w the centre which is also equal to the height of cylinder
2007-02-03 19:12:54 · answer #1 · answered by n nitant 3 · 0⤊ 1⤋
It's impossible to tell with the little information you've given. What precisely do you mean by the belt being "tightly tied to a cylinder"? If the belt is tied around the middle so that it runs parallel with the circumference, this wouldn't match the circumference for a radius of 0.5 ft, and even if it the cylinder's height could still be anything.
If you mean that the belt is tied lengthwise, so that it stretches across the height of the cylinder, goes across the center of one circle, then comes around the back, wraps over the center of the other circular end, etc. then you could calculate the height of the cylinder (and thus the distance between the two faces). The belt would then stretch for the lengths of two heights plus two diameters, so 2h + 2*1 = 15, and h = (15 - 2)/2 = 13/2, or six and a half feet.
2007-02-04 03:27:34 · answer #2 · answered by Anonymous · 0⤊ 2⤋
I can't picture the arrangement of the circles and the cylinder or do you mean spheres and cylinder?) Please describe it unambiguously so we can help. When you say "both ends of the cylinder" I would say the ends are 15 feet apart, so the centers of the circles (one on each end) are 15 feet apart. But that doesn't seem like much of a question.
2007-02-04 03:20:12 · answer #3 · answered by Northstar 7 · 0⤊ 1⤋
I'm sure someone with auto-cad could draw this up and give you an answer in less time it would take to do the math. I could but I don't have mine installed right now.
2007-02-04 03:18:11 · answer #4 · answered by mazaker2000 3 · 0⤊ 2⤋
one more detail is required
2007-02-04 03:25:12 · answer #5 · answered by Mritunjay 2 · 0⤊ 1⤋
YA THATS SIMPLE.......IT IS JUST 15 SINCE IT IS COMPLETELY TIED TIGHTLY OVER THECYLINDER...THATS IT...............SEEYOU AGAIN....BYE.........
2007-02-04 03:13:20 · answer #6 · answered by sudarshan s 1 · 0⤊ 2⤋