find a polynomial with leading coefficient 1 and degree 3 that has -1, 1 and 3 as roots?

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2007-02-03 16:52:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

An equation with roots -1,1 & 3 is given as

(x+1)(x-1)(x-3) =0.

Expanding the above equation, we get

x^3 - 3x^2 - x +3 = 0.

2007-02-03 17:42:39 · answer #1 · answered by Anonymous · 1⤊ 0⤋

find a polynomial with leading coefficient 1 and degree 3 that has -1, 1 and 3 as roots.

f(x) = (x+1)(x-1)(x-3)

2007-02-04 01:07:46 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋

x^3 - 3x^2 - x + 3

2007-02-04 00:56:10 · answer #3 · answered by sarajschryver 2 · 0⤊ 0⤋

(x+1)(x-1)(x-3)
=(x^2-1)(x-3)
=x^3-3x^2-x+3

2007-02-04 00:59:14 · answer #4 · answered by raj 7 · 0⤊ 0⤋

raj is right

2007-02-04 01:20:57 · answer #5 · answered by lambdamuomega1 2 · 0⤊ 0⤋