Help me combine these statistics please?

0 ⤊

Help me combine these statistics please?

I am not a math person. I want to combine the chance of something happening with these four numbers. 38%,33%,60%,36%
what is the chance of at least one of those things occurring?

2007-02-03 16:05:01 · 3 answers · asked by insenid 1 in Science & Mathematics ➔ Mathematics

3 answers

The probabilities total more than 1, so the events aren't mutually exclusive.
Let's try
P = (1 - (1 - .38)(1 - .33)(1 - .6)(1 - .36)
P = (1 - (.62)(.67)(.4)(.64)
P = 0.8936576

2007-02-03 16:24:41 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

38% + 33% + 60 % + 36% = 167/4 = 41.5%

2007-02-04 00:27:01 · answer #2 · answered by romeo_1595 2 · 0⤊ 0⤋

dont go by this answer, its just a guess..... 42.5%?

2007-02-04 00:15:45 · answer #3 · answered by <3 3 · 0⤊ 1⤋