Algebra percents?

Question

Laura invested $2000, some at 8% annual simple interest and the rest at 10% annual simple interest, giving her a total return of $176 per year. How much did she invest at 8%?

Answer 1

Let x= amount of the $2000 whole invested at 10%
Then 2000-x = amount invested at 8%

0.08(2000-x) + 0.10x = 176
160 - 0.08x + 0.10x = 176
-0.08x + 0.10x = 176-160
0.02x = 16
x = 800

So going back to the setup above:

Amount invested at 8%= 2000-x = 2000-800 = $1200

Answer 2

Let x represent what she invested at 8% (or .08), and 2000-x is the amount invested at 10% (.10). .08x + .1(2000-x) = 176.

Answer 3

Use A=Pe^(rt)
Where A= the ending amount
P=the beginning amount
e=e
r=the rate in your case 8% or 10% per year
and t = time (years)

this should help you do your homework

Answer 4

ok, because you're fixing equations, i am going to set up a percentage. 5% is an similar as 5/one hundred. (continually change the % to a fragment). it truly is an similar as a pair huge variety x over eighty, because all of us comprehend that 5% of eighty is smaller than eighty, so x is interior the numerator. So what you've is: 5/one hundred=x/eighty. (once you do percents x is continually on excellent of the massive variety you're looking the % of). Now, remedy through flow multiplying - muliply the 5 and the eighty together because they're diagonals, and one hundred and x because they're diagonals (flow throughout, or diagonal in flow multiplying). this gives you with a sparkling equation of four hundred=100x. All that is left to do is to divide both side through one hundred to get x remoted, and your answer is x=4. wish this helps! again: set up percentage: 5/one hundred=x/eighty flow multiply: 5(eighty)=one hundred(x) Simplify: 400=100x Divide through one hundred: x=4