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i got as far as sqrt a^2/sqrt b^3 Xsqrt b^2 is that as far as it can go? when you have a sqrt a/bsqrta^2/b^2 do you multiply them to get sqrt a^3/b^3??

2007-02-03 12:32:05 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

sqrt (a^2/b^5)
= (sqrt a^2)/ (sqrt b^5)
= a/ [(sqrt b^4) (sqrt b)]
= a/[b^2(sqrt b)]

2007-02-03 12:38:27 · answer #1 · answered by sciencewiz 4 · 0 1

you can simplify sqrt(b^2) as just !b! (absolute value of b), so you could simplify sqrt a^2/ sqrt b^3 as a / b^3/2 (that's b to the 3/2 power)

yes, if you have sqrt (a/b) * sqrt(a^2/b^2), you can just multiply the insides and say that's sqrt(a^3/b^3) or a^3/2 / b^3/2

2007-02-03 12:39:48 · answer #2 · answered by koolkat 3 · 0 1

b^5 is written as b^2 x b^2 x b

sqrt then becomes bxbxsqrt(b)

so, b^2 x sqrt(b)

2007-02-03 12:40:47 · answer #3 · answered by Sid 2 · 0 1

use bracket to make your question clear.
assuming what you mean SQRT(a^2/b^5) then
SQRT(a^2/b^5)=a^(2/1)/b^(5/2)
tony.q.

2007-02-03 12:44:09 · answer #4 · answered by Anonymous · 0 1

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