2007-02-03 12:03:07 · 4 answers · asked by Phil 1 in Science & Mathematics ➔ Mathematics
A^2 - A = A(A-1)
X^2 +X - 6 = (X + 3)(X - 2)
2X^2 - 8 = 2(X^2 - 4) = 2(X-2)(X+2)
X^3 + 8 = (X+2)( X^2-2X+4)
2007-02-03 16:32:03 · answer #1 · answered by MATHMANRET 2 · 0⤊ 0⤋
To factor the first, remove the common element from each term. Hence a^2-a factored becomes a(a-1).
For the second, you have to use what I call reverse FOIL. The quadratic x^2+x-6 becomes (x+3)(x-2).
The third is similar to the second. Factor using the reverse FOIL method to obtain (2x+4)(x-2).
2007-02-03 20:16:22 · answer #2 · answered by sciencewiz 4 · 0⤊ 0⤋
1. a(a-1)
2. (x + 3) (x - 2)
3. 2(x^2-4)
4. (x+2)(x-2)(x-2)
2007-02-03 20:08:57 · answer #3 · answered by Shredded Cottage Cheese 6 · 0⤊ 0⤋
i think i had that same question ahha
2007-02-03 20:20:17 · answer #4 · answered by Runningback1692 2 · 0⤊ 0⤋