if 50 mL of water at 22.3 degrees C is mixed with 50 mL of water at 47.7 degree C in such a way that no heat i

Question

a) if 50 mL of water at 22.3 degrees C is mixed with 50 mL of water at 47.7 degree C in such a way that no heat is lost to the environment, what will be the temperature of the final mixture?

b) if 50 mL of water at 22.3 degrees C is mixed with 50mL of water at 47.7 degree C in a calorimeter with Ccal= 20.0 J/Degree C, what will be the temperature of the final mixture?

Thank you so much!

Answer 1

a) if 50 mL of water at 22.3 degrees C is mixed with 50 mL of water at 47.7 degree C in such a way that no heat is lost to the environment, what will be the temperature of the final mixture?

Let T = temperature of mixture

100 T = 50(22.3°) + 50(47.7°)
100T = 3500
T = 35° C