2007-02-03 11:47:35 · 4 answers · asked by Latina Hottie! W.Chocolate 2 in Science & Mathematics ➔ Mathematics
4x^2 + 3k between 2x + 1
2007-02-03 11:48:46 · update #1
f(x) = 4x^2 + 3k
From 2x+1=0,x=-1/2
f(-1/2) = 4(-1/2)^2 + 3 = 0
Solve for k,
k = -1/3
2007-02-03 12:13:56 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
Divide 4x^2 + 3k by 2x + 1 and you will get 2x - 1 with a reminder of -1. This means tht if the divisin is to come out even, 3K must be = -1. So k = -1/3.
2007-02-03 20:08:44 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
So you want to know what values for k make
(4x^2 + 3k) / (2x + 1) exact?
What we have to do is long division.
(2x + 1) INTO (4x^2 + 3k)
Long division is difficult to show on here, but after long division, you should get a quotient of (2x - 1) and a remainder of 3k + 1.
Long division is exact when the remainder is equal to 0; therefore, we equate 3k + 1 to 0
3k + 1 = 0, so
3k = -1
k = -1/3
2007-02-03 20:07:19 · answer #3 · answered by Puggy 7 · 0⤊ 0⤋
I strongly suggest you rewrite your question in an intelligible way.
2007-02-03 20:00:47 · answer #4 · answered by Steiner 7 · 0⤊ 0⤋