how do you derivative x^2-14x-16?

Question

what are the steps to derivative this forumula?

Answer 1

welp, take each part in sections. for x^2, add multiply by the exponent, and subtract 1 from the exponent. 2x^1. K?

Then repeat for the -14x. The exponent is 1 so multply by 1 and subtract 1 from the exponent. -14x^0.

For -16, this is really -16x^0, therefore multiplying by 0 gives you 0.

so you get 2x-14, k?

Answer 2

When you do a derivative you put the exponent in the front and substract 1 from the exponent. Since 16 doesn't have an x, it's derivative is 0. The derivative of a constant is 0.

The result is:
2x - 14

Hope it helps!

Answer 3

There are three facts you need:

1. The derivative of a sum of things is equal to the sum of the derivatives of the parts.

2. The derivative of ax^n = a*n*x^(n-1)

3. The derivative of a constant is zero.

So -- deriv of x^2 is 2x
Deriv of -14x is -14
Deriv of -16 is zero

Add them up & you get:

2x-14

Answer 4

There is a shortcut to taking a derivative... if you take the exponent and subtract 1 from it and then multiply the number with the former exponent, you will find the first derivative.
In other words
f(x) = ax^c
f'(x) = acx^(c-1)

so, in this case

f(x) = x^2 -14x - 16
f'(x) = 2x - 14 - 0
f'(x) = 2x - 14