I've reacted 4 acids w/ the base NaOH at 2M. The acids are H2SO4, HNO3, HCl, and acetic acid. I did 2 trials for each acid, one with 1M acid and one with 2M acid. I then recorded the temp. change.
Also, I need to figure out the heat released per acidic hydrogen and heat released per mole of water formed.
2007-02-03 06:48:40 · 3 answers · asked by Andrea 1 in Science & Mathematics ➔ Chemistry
Use Q = mc x delta T to work out the heat released for the particular quantity of acid that you used.
Use moles = volume x molarity/1000 to work out the actual number of moles of acid.
Then divide the heat output by the moles! This will give heat released per mole of acid, which for HNO3, HCl and CH3COOH will also be per mole of acidic H. For H2SO4 you need to double the answer for the two Hs.
For H2SO4, this will also be the heat released per mole of water. You will need to double the others.
The enthalpy of neutralisation of most strong acids is around 57kJ per mole, and if you get that answer, you will know that you are on the right track!
2007-02-03 07:04:36 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
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2016-05-16 18:52:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i think h2so4 has more heat as 2 hydrogen evolved
2007-02-03 07:01:14 · answer #3 · answered by Anonymous · 0⤊ 1⤋