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x,y.. line 1... line 2... both lines... neither line

(-9,5)

(-7,4)

(6,6)


place an X under the appropriate catagory

2007-02-03 05:18:17 · 3 answers · asked by crimesucks06 1 in Science & Mathematics Mathematics

3 answers

You forgot to include the equations for the lines, but here's how you'd do this...
Generally you have equations for lines, these equations might look like this:
y = 4x + 3
y = 5x, etc
These equations would be in slope intercept form.
Or they might look like this:
3x + 2x = 6 etc
These equations would be in standard form.
So what you'd do is, you'd replace the first number in each pair with the "x" in the equation, and the second number in each pair with the "y" in the equation. If it works, then the point is on the line. If it doesn't work, then the point is not on the line.
For example, let's see if (2, 8) is on the line y = 3x + 2
Replace the x with 2, the first number, and the y with the second number, 8
Now, 8 = 3(2) + 2 = 5 + 2 so that pointis on the line y = 3x + 2.
Consider a different point, (-9,5)
5 = 3(-9) + 2 = (-27)+ 2 = -25
false
So that point, (-9,5) is not on the line.
So try the points you are given in the lines that you are given and you can tell if they are on the line or not.

2007-02-03 05:26:26 · answer #1 · answered by Joni DaNerd 6 · 1 0

Um, what are the equations for line1 and line2? Can't help out unless that information is present.

2007-02-03 05:25:22 · answer #2 · answered by lizzy208_ayla 2 · 0 0

complicated matter. seek with yahoo and bing. just that may help!

2014-12-04 15:52:24 · answer #3 · answered by Anonymous · 0 0

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