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8 answers

8x^2 -2x -3 = 0
----------------------
4x ---- -3
-----x-----
2x ---- 1
-----------------------
cross multiply = -2x
-----------------------

8x^2 -2x -3 = (4x-3)(2x+1)

(4x-3)(2x+1) = 0

x= -1/2 or 3/4

2007-02-03 05:26:18 · answer #1 · answered by Geinius 3 · 0 0

I am assuming that this expression is equal to zero and you want to solve for x:

8x^2 -2x -3 = 0

the easy way on this expression would be to factor it:

(2x+1)(4x-3) = 0
this can be true only if one of the factors are equal to zero

set each factor equal to zero and solve for x:

2x+1 = 0 therefor x = -1/2

4x-3 = 0 therefor x= 3/4

the above are the two solutions of the given expression.
you get 2 solutions or roots because x was to the second power in the given problem.

2007-02-03 05:38:39 · answer #2 · answered by bignose68 4 · 0 0

You could use the quadratic formula.

Heres the website where you can find the formula..It's too difficult to type here. http://www.purplemath.com/modules/solvquad4.htm

so in your equation 8x^2 - 2x -3, a=8, b= -8, and c= -3

so where its -b on the formula, ur going to plug in -(-8) so it will become positive 8. then under the square root its (-8)^2 - 4(8) (-3)
understand? you're just plugging in and then on the bottom ur gonna plug in 2(8). and then solve. remember u need to do -(-8) + the square root stuff divided by the 2(8) and then u need to do
-(-8) - the square root stuff divided by the 2(8).

Im not very good at explaining but i hope it helps a little bit!

2007-02-03 05:20:53 · answer #3 · answered by JhoAnNaBaNAnA 1 · 0 0

I assume the equation is 8x^2 -2x -3=0

The quickest way is to use the equation for the solving of a quadratic equation:

x= -b+-sqrt (b^2-4*a*c)
-------------------------
2a

Where a =8, b=-2 and c=-3 and sqrt is the square root.

x= +2+- sqrt (4+4*8*3)
-------------------------
16

This simplifies to

x= +2+-sqrt (100)
---------------------
16

Therefore x roots are

x= (+2+10 )/16 and x= (+2-10)/16

The roots are 12/16 and -8/16, which simplifies to 3/4 and -1/2.

2007-02-03 05:24:04 · answer #4 · answered by The exclamation mark 6 · 0 0

8x^2-2x-3=0
(4x-3)(2x+1)=0
4x-3=0
4x=3
x=3/4

2x+1=0
2x=-1
x=-1/2


ok its hard to explain, but here goes. you have to factor the polynomial using FOIL. FOIL stands for First-Inner-Outer-Last.
(4x-3) (2x+1)

The "First" values are 4x and 2x. We multiply these two to get 8x^2, which is the first value of the polynomial.

The "Outer" values are 4x and 1. We multiply these and get 4x
The "Inner" values are -3 and 2x. We multiply these and get -6x
Now when we add the two products together to get +4x-6x we get -2x, which is the middle term of the polynomial.

The "Last" values are -3 and +1. We multiply these and get -3, which is the last value of the polynomial.

You have to play around with different factors to get this to work.
Once you have the factors, set them = to 0 and solve.

2007-02-03 05:38:38 · answer #5 · answered by tma 6 · 0 0

Use
D= (B^2) - 4AC

Here B= -2, A= 8 and C= -3

D= 4- (4(8)(-3))= 100

x= (-B + (D)^ 1/2)/2A
and x= (-B- (D)^1/2)/2A

so x=3/4 and x= -1/2

2007-02-03 05:16:13 · answer #6 · answered by Anonymous · 0 0

as it is a quadratic eqn, so ut will have 2 answers let: A and B. now yer eqn. is in the form ax^2 +bx+c right.[here a=8,b=(-2) and c=(-3)]. got it? good!
then put the formula [b+/- (b^2 -4ac)]/2a ok.[+/- means put + to get A and - to get B or vice versa.] A & B are the roots or answers . pls tremember it. dnt lose marks buddy exams r close. do well man!!

2007-02-03 05:25:23 · answer #7 · answered by Rishi k 2 · 0 1

x="(-B+or-squrt(B^2-(4*A*C)))/(2A)
X=--2+ root of (4- (-3*4*8))/2*8
=2+10/16=0.75
or=2-10/16=-0.5
answer is .75 and .5
or u can do it like that
8x^2-2x-3=(6x-3)(4/3x-1)=0

2007-02-03 05:29:02 · answer #8 · answered by kater al nada 2 · 0 1

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