How do you solve for exponents? What is the value of X?
2007-02-03 04:51:33 · 7 answers · asked by pazdon 1 in Science & Mathematics ➔ Mathematics
2.718^X = 6
Use logarithms:
log(2.718^X)=log(6)
X (log2.718)=log(6)
x* (0.434)=(0.778) and solve for X
2007-02-03 04:57:41 · answer #1 · answered by Jerry P 6 · 0⤊ 0⤋
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2016-12-13 07:59:26 · answer #2 · answered by casco 4 · 0⤊ 0⤋
Take the logarithm base 10 of each side.
log 2.718 to the power of X = log 6.00
Because of logarithm exponent properties:
X * log 2.718 = log 6.00
Divide both sides by log 2.718:
X = (log 6.00) / (log 2.718)
Type (log 6.00) / (log 2.718) into your calculator to get the answer!
2007-02-03 04:57:48 · answer #3 · answered by Ptrain 1 · 1⤊ 0⤋
2.718^x = 6
Taking logs on both sides:
x * log(2.718) = log(6)
x = log(6)/log(2.718)
If you need the value as a decimal, use a scientific calculator to calculate the logs.
If 2.718 should be actually e = 2.71828182845..., the equation would be
e^x = 6
x = ln(6)
Please see the sources below.
2007-02-03 05:10:33 · answer #4 · answered by jcastro 6 · 0⤊ 0⤋
2.718^x = 6
2.718 is a number with special properties and is referred to as e
Thus e^x = 6
Take log base(e) of both sides:-
loge (e^x) = loge(6)
x loge(e) = loge 6
x = loge 6 = 1.79
This can be checked by calculator by doing the calculation 2.718^(1.79)
Answer is 6 as required.
2007-02-03 05:09:45 · answer #5 · answered by Como 7 · 0⤊ 0⤋
2.718^(X)=6
Take logarithm to the base 10 or e(depends on you) for both sides.
So,log (2.718^X)=log 6
or,Xlog 2.718=log 6[since log (a^b)=b(loga)]
or,X=1.791
2007-02-03 05:03:51 · answer #6 · answered by gmajumdar_86 2 · 0⤊ 0⤋
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2007-02-03 04:55:23 · answer #7 · answered by I Am A French Fry 2 · 0⤊ 1⤋