2007-02-03 04:13:29 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
CuCO3 ---> CuO + CO2
2007-02-03 04:15:55 · answer #1 · answered by TheOnlyBeldin 7 · 1⤊ 0⤋
The other answerers are right:
CuCO3(s) ---> CuO(s) + CO2(g)
This is, in fact, an over-simplification, because the stuff that is sold by chemical suppliers as 'copper(II) carbonate' is never exactly CuCO3. It's a non-stoichiometric compound and its formula is better represented as: CuCO3(CuO)n, where n is between 0·1 and 0·15, depending on the method of production.
2007-02-04 12:15:46 · answer #2 · answered by deedsallan 3 · 0⤊ 0⤋
CuCO3 -----> CuO + CO2 (delta)H > 0 KJ/mol
Assuming copper means Cu(II)
2007-02-03 04:29:37 · answer #3 · answered by SS4 7 · 0⤊ 0⤋
Copper Oxide which I seem to recollect is white and Carbon Dioxide which is a clear gas.
2007-02-05 06:55:17 · answer #4 · answered by Professor 7 · 0⤊ 0⤋
when copper carbonate is heated it is decomposed in copperoxide and carbondioxide
2007-02-03 04:23:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋
CuCO3 ---> CuO + CO2
2007-02-03 05:07:53 · answer #6 · answered by chelle_reeder 1 · 0⤊ 0⤋
CuCO3(s) = CuO(s) + CO2(g)
2007-02-03 08:20:44 · answer #7 · answered by lenpol7 7 · 0⤊ 0⤋