lim . . . . . . . . (x^2 - 9)/(x^3+ 27)
x=>-3
2007-02-03 04:08:16 · 5 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics
yep, i got the same thing
2007-02-03 04:11:55 · answer #1 · answered by andrew R 2 · 1⤊ 0⤋
You have a zero over zero, so you must find a common factor in the top and bottom, which happens to be x+3. You have to do synthetic division for the bottom equation to find the other factor of the denominator. You would get x^2-3x+9. You cross out the x+3 on the top and the bottom of the equation and then you plug a -3 into the equation. You would get a -1/4.
2007-02-03 04:18:34 · answer #2 · answered by Steve Z 3 · 0⤊ 0⤋
The TI-eighty 3 would not help logarithms with bases different than 10. with the intention to log_2, you will might desire to apply the replace of Base theorem, which states that: log_b (x) = log(x)/log(b). In different words, log_2(9) ? log_2(9/sixteen) might desire to be written as log(9)/log(2) ? log(9/sixteen)/log(2). Typing that into your calculator grants you the predicted 4.
2016-10-01 09:00:27 · answer #3 · answered by ? 4 · 0⤊ 0⤋
-2 is the correct answer.
2007-02-03 04:12:45 · answer #4 · answered by eva 3 · 0⤊ 1⤋
TAKE (X+3) COMMON AND PROCEED
2007-02-03 04:13:18 · answer #5 · answered by vyral_143 1 · 1⤊ 0⤋