A sample of sulfur having a mass of 1.28 g combines with oxygen to form a compound with a mass of 3.20 g. What is the empirical formula of the compound?
2007-02-03 04:05:24 · 3 answers · asked by jsock 1 in Science & Mathematics ➔ Chemistry
1.28 g of sulfur is 0.04 moles of sulfur
The remaining 1.92 grams is oxygen, which is 0.12 moles of oxygen.
So there are 3 moles of oxygen for 1 mole of sulfur, thus the empirical formula is SO3.
2007-02-03 04:09:40 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
take the mass of sulfer and divide by the atomic weight = .04 moles
take the mass of oxygen and divide by the atomic weight =.12 moles
since you have 3 times as many moles of oxygen to sulfer your emperical formula is SO3
2007-02-03 12:10:21 · answer #2 · answered by andrew R 2 · 0⤊ 0⤋
i think that the compound is the same as the mass i think!!!!!!!!
2007-02-03 12:11:55 · answer #3 · answered by frannie 1 · 0⤊ 1⤋