∫ (2x + 7)^3/5 dx =?

Question

Does this look correct?

∫(3/5)(2x + 7)^3/5 dx
= (3/5)(1/2)(5/8)(2x + 7)^8/5 + C
= (3/16)(2x + 7)^8/5 + C

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other book solutions


a. (3/16)(2x + 7)^8/5 + C

b. (5/16)(2x + 7)^8/5 + C

c. (1/2)(2x + 7)^8/5 + C

d. (25/128)(2x + 7)^8/5 + C

e. (24/25)(2x + 7)^3/5 + C

f. (5/8)(2x + 7)^8/5 + C

or none of these

Answer 1

I don't know which question do you ask.
∫ (2x + 7)^3/5 dx
= (5/8)(1/2)(2x+7)^8/5 + C
= (5/16)(2x+7)^8/5 + C
Answer is b.

or

∫ (3/5)(2x + 7)^3/5 dx
= (3/5)(5/8)(1/2)(2x+7)^8/5 + C
= (3/16)(2x+7)^8/5 + C
Answer is a.

So, answer is different depending on different question

Answer 2

=(5/8)(1/2)(2x+7)^8/5
=(5/16)(2x+7)^8/5=b
∫ ax^n dx= [ax^(n+1)]/[(n+1)(a)]

Answer 3

what was the question is it or are you just asking us if it is right welll anyway i don't think that is a question didn't work on my calculator well i don't have a peice of paper so i can't work it out sorry

Answer 4

the option (b) is the correct solution for your question.