They could be on either brand. But they need to be wrestling now. Also you can choose people from TNA.
2007-02-03 02:34:19 · 13 answers · asked by ? 3 in Sports ➔ Wrestling
Randy Orton v. the texas rattlesnake"Austin" inside a hell in a cell.
Randy to win it on top of the cage with a RKO from out of nowhere, imagine me running to congratulate Randy, he kisses me in the ring.
2007-02-03 03:33:03 · answer #1 · answered by Redhead Kicki 2 · 0⤊ 0⤋
Shawn Michaels VS John Cena for the WWE Championship
2007-02-03 10:36:54 · answer #2 · answered by Blah 2 · 0⤊ 0⤋
It would have to be somekind of extreme match - im thinking a tornado tag match between the Hardys from smackdown and raw against Sabu and RVD maybe tables ladders chairs
that sounds like a match id pay to see
close 2nd would be DX v VKM
2007-02-03 11:01:24 · answer #3 · answered by andi 2 · 0⤊ 0⤋
A triple threat ladder match between Shawn Micheals, AJ Styles, and Chris Benoit.
2007-02-03 10:39:37 · answer #4 · answered by jm42445 5 · 0⤊ 0⤋
Undertaker has been beginning a feud with Batista, when he accidentally screwed him out of hiis chance at being in the Royal Rumble Match- Kennedy vs.Batista vs. The Undertaker. So I guess he'll challenge for the WH title.
2007-02-03 11:04:55 · answer #5 · answered by WizAW3S0ME 5 · 0⤊ 0⤋
Andre the Giant vs. Carey VonErick
2007-02-03 10:36:46 · answer #6 · answered by i_liked_dos 3 · 0⤊ 0⤋
Rey Mysterio vs Chavo Guerrero
Hell In a Cell Match..
and Rey will win xD..
2007-02-03 10:53:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
to mix the brands together but
cena vs batista vs lashley vs taker vs hbk the winner is the undisputed champio get a new belt and all the brands combine
2007-02-03 10:54:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋
best match? dream match? dont understand the question..but here i go with an answer...
undertaker vs shawn michaels
2007-02-03 10:47:16 · answer #9 · answered by Isuck,Usuck,Weallsuck 3 · 1⤊ 0⤋
undertaker vs. shawn micheals ironman match
2007-02-03 10:58:50 · answer #10 · answered by Anonymous · 0⤊ 0⤋