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3 answers

false

ln(a/b) = lna - lnb

NOT ln(a)/ln(b) = lna-lnb

2007-02-03 02:29:28 · answer #1 · answered by Anonymous · 1 0

well as a matter of fact the answer is false
because ln(a*b)=ln(a)+ln(b)
now let we have ln(a/b)
so ln(a/b)=ln(a*(1/b))=
ln(a)+ln(1/b)
and ln(1/b)=-ln(b)
so ln(a/b)=ln(a) -ln(b) not ln(a)/ln(b)
ln(a)/ln(b)=loga in the base of b loga_(b) well ican not show it here

2007-02-03 10:37:07 · answer #2 · answered by vinchenzo_corleone 2 · 0 0

False loga-logb = log(a/b)

2007-02-03 19:55:29 · answer #3 · answered by santmann2002 7 · 0 0

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