Find the repulsive force between a helium nucleus and a proton separated by a distance of 1.00x10^-14m, and the approximate maximum diameter of a single nucleus.
2007-02-03 01:22:19 · 3 answers · asked by Yee Haw 1 in Science & Mathematics ➔ Physics
You need to use the Equation of Coulomb Repulsion-:
F = q1 x q2 x r
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4 x pi x Epsilon x r^2
Therefore-:
F = 1.6 x 10^-19 x 3.2 x 10^-19 x 1 x 10^-14
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4 x pi x 8.85x^-12 x (1 x 10^-14)^2
F = 4.60 x 10^-14 Newtons
The Force is Repulsive as the charges are alike (in this case both the Proton and the Helium Nucleus are positive.)
2007-02-06 21:59:43 · answer #1 · answered by Doctor Q 6 · 0⤊ 0⤋
It can be calculated by using coulombs law
2017-04-02 00:24:38 · answer #2 · answered by u will come to know 1 · 0⤊ 0⤋
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2016-11-24 20:54:08 · answer #3 · answered by jandrey 4 · 0⤊ 0⤋