the base of the pyramid is a rhombus whose diagonals is 12 cm., and 16 cm. The height of the pyramid is 6.4 cm., and passes through the point of intersection of the base diagonals.
2007-02-03 01:03:38 · 2 answers · asked by jonah 1 in Science & Mathematics ➔ Mathematics
so the base is 4 right triangles - each having a side of 8cm and 6 cm
which is double the 3-4-5 triangle - so each side is 10
squaring 64 + 36 = 100 sq root of 100 is 10
so your volume is b x b x 1/2 hgt
10 x 10 x 3.2
320 sq cm
area on the base of the pyramid - would be 10 x 10 = 100
right ?
2007-02-03 01:11:59 · answer #1 · answered by tom4bucs 7 · 0⤊ 0⤋
well work out the area of the rhombus (12 times 16) then work ou tthe areas for each of the sides DO YOUR OWN HOMEWORK YOU NEED TO START THINKING OR STAY STUPID your choice
2007-02-03 01:07:21 · answer #2 · answered by mr_soapytitwank 3 · 0⤊ 0⤋