physics question?

4 ⤊

Two planes approach each other head-on. Each has a speed of 725 km/h, and they spot each other when they are initially 12.0 km apart. How much time do the pilots have to take evasive action?

2007-02-02 16:57:23 · 2 answers · asked by Jessie L 2 in Science & Mathematics ➔ Physics

2 answers

Relative speed of 2*725=1450km/hr
12km/1450km/hr*3600s/hr=29.79secods

2007-02-02 17:42:55 · answer #1 · answered by Anonymous · 2⤊ 0⤋

Their relative speed is 2*725 = 1450.

Speed * Time = Distance.

Speed and Distance are known.

You can take it from there.

2007-02-03 01:01:35 · answer #2 · answered by Curt Monash 7 · 2⤊ 0⤋