Actually this is based on truth.
It has become known as "The Birthday Paradox" although it is not technically a paradox.
The exact number is 23 people which results in a ~50.73% chance of having duplicate birthdays. (how this is derived can be found at my first source.)
For a more visual explanation see this graph:
http://en.wikipedia.org/wiki/Image:Birthday_paradox.png#file
See this in action at this virtual party:
http://projects.felipc.com/birthday-paradox/
2007-02-03 09:52:28
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answer #1
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answered by memeluke 4
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False
2007-02-02 16:51:21
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answer #2
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answered by exon111 2
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False
2007-02-02 16:49:45
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answer #3
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answered by Anonymous
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False
2007-02-02 16:50:05
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answer #4
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answered by Anonymous
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False
2007-02-02 16:49:44
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answer #5
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answered by Tuco 2
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False
2007-02-02 16:49:41
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answer #6
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answered by Backwoods Barbie 7
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False cuz there are 365 days in a year...and the odds of 2 having the same should be quite lower than 1/2.
2007-02-02 16:49:38
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answer #7
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answered by kowalley 5
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I believe if you take 22 people, the odds are even higher (by a lot). It's 95% or something. This means the birthday itself, though, not always the year included. It's still strange, but true.
2007-02-02 16:50:04
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answer #8
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answered by ♥♫!♫♥ 3
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I'd have to go with False. There are 365 days in a year. The chances are 1 in about 150 chances of that happening.
2007-02-02 16:51:57
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answer #9
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answered by crazyqa215 1
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By my calculations (done in a Microsoft Excel Spreadsheet)...
for 20 people the odds are about 58.86% that no two of them have the same birthday.
for 22 people the odds are about 52.43%, and
for 23 people the odds are about 49.27%
(I've disregarded the possibility of a Feb 29th birthday just to make the calculations simpler)
2007-02-02 16:58:22
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answer #10
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answered by Andrew 6
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