-9y^5/1/3y^6?

Question

is the correct answer y/27

Answer 1

Those are correct, but when I first looked at it, this is how it looked to me . . .
(-9y^5)/[(1/3)y^6]. If this is the case, the 1/3 would become a 3 in the numerator.
(-27y^5)/y^6. Then subtract the 6 from the 5 because they're exponential powers in a fraction with the same base.
-27y^(-1) or -27/y.

Answer 2

No, it can only be written as = - 9*y^5 / {3*y^6}^-1

= - 9 * y^5 * (3 * y^6) = -27 y^11

Answer 3

it depends in which order you do divisions
if the first divide (-9y^5)by 1 and then by 3y^6 then it is -9y^5/3y^6
if you first divide(1) by 3y^6 and then divide -9y^5 by the result then you get -27y^11

In general the first division is denoted by a smaller line.